2x^2-32/8x-32

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Solution for 2x^2-32/8x-32 equation: 


x in (-oo:+oo)

2*x^2-((32/8)*x)-32 = 0

2*x^2-4*x-32 = 0

2*x^2-4*x-32 = 0

DELTA = (-4)^2-(-32*2*4)

DELTA = 272

DELTA > 0

x = (272^(1/2)+4)/(2*2) or x = (4-272^(1/2))/(2*2)

x = (4*17^(1/2)+4)/4 or x = (4-4*17^(1/2))/4

x in { (4-4*17^(1/2))/4, (4*17^(1/2)+4)/4 }

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